Base | Representation |
---|---|
bin | 100101011100010011000… |
… | …1110010101010011110001 |
3 | 200012221202102122221112101 |
4 | 1022320212032111103301 |
5 | 1133303013100041423 |
6 | 14540013442500401 |
7 | 1040533656144115 |
oct | 112704616252361 |
9 | 20187672587471 |
10 | 5146012112113 |
11 | 17044587544a4 |
12 | 6b13b9064701 |
13 | 2b43613a3042 |
14 | 13b0d5657745 |
15 | 8dcd616e7ad |
hex | 4ae263954f1 |
5146012112113 has 2 divisors, whose sum is σ = 5146012112114. Its totient is φ = 5146012112112.
The previous prime is 5146012112029. The next prime is 5146012112119. The reversal of 5146012112113 is 3112112106415.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4959916505569 + 186095606544 = 2227087^2 + 431388^2 .
It is a cyclic number.
It is not a de Polignac number, because 5146012112113 - 233 = 5137422177521 is a prime.
It is not a weakly prime, because it can be changed into another prime (5146012112119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2573006056056 + 2573006056057.
It is an arithmetic number, because the mean of its divisors is an integer number (2573006056057).
Almost surely, 25146012112113 is an apocalyptic number.
It is an amenable number.
5146012112113 is a deficient number, since it is larger than the sum of its proper divisors (1).
5146012112113 is an equidigital number, since it uses as much as digits as its factorization.
5146012112113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1440, while the sum is 28.
Adding to 5146012112113 its reverse (3112112106415), we get a palindrome (8258124218528).
The spelling of 5146012112113 in words is "five trillion, one hundred forty-six billion, twelve million, one hundred twelve thousand, one hundred thirteen".
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