Base | Representation |
---|---|
bin | 10111011010001011011000… |
… | …10111001100001111111011 |
3 | 20202021011010201020021012121 |
4 | 23231011230113030033323 |
5 | 23221344344232430441 |
6 | 301252112520022111 |
7 | 13562043034330354 |
oct | 1355055427141773 |
9 | 222234121207177 |
10 | 51477001061371 |
11 | 15447301107486 |
12 | 5934707601937 |
13 | 229535005c552 |
14 | c9d700580d2b |
15 | 5e407cd58dd1 |
hex | 2ed16c5cc3fb |
51477001061371 has 12 divisors (see below), whose sum is σ = 54683780377840. Its totient is φ = 48448411182720.
The previous prime is 51477001061179. The next prime is 51477001061383. The reversal of 51477001061371 is 17316010077415.
It is a de Polignac number, because none of the positive numbers 2k-51477001061371 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (51477001061471) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 26804041 + ... + 28660261.
Almost surely, 251477001061371 is an apocalyptic number.
51477001061371 is a deficient number, since it is larger than the sum of its proper divisors (3206779316469).
51477001061371 is a wasteful number, since it uses less digits than its factorization.
51477001061371 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1952214 (or 1952197 counting only the distinct ones).
The product of its (nonzero) digits is 123480, while the sum is 43.
The spelling of 51477001061371 in words is "fifty-one trillion, four hundred seventy-seven billion, one million, sixty-one thousand, three hundred seventy-one".
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