Base | Representation |
---|---|
bin | 1110111111000010011… |
… | …01110100100110001011 |
3 | 1211012222211210222012212 |
4 | 13133201031310212023 |
5 | 31413433134331011 |
6 | 1032311000455335 |
7 | 52125124301333 |
oct | 7374115644613 |
9 | 1735884728185 |
10 | 514879605131 |
11 | 1893a5129021 |
12 | 8395417a54b |
13 | 39725a62258 |
14 | 1acc54680c3 |
15 | d5d70b508b |
hex | 77e137498b |
514879605131 has 2 divisors, whose sum is σ = 514879605132. Its totient is φ = 514879605130.
The previous prime is 514879605127. The next prime is 514879605133. The reversal of 514879605131 is 131506978415.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 514879605131 - 22 = 514879605127 is a prime.
It is a super-2 number, since 2×5148796051312 (a number of 24 digits) contains 22 as substring.
Together with 514879605133, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 514879605131.
It is not a weakly prime, because it can be changed into another prime (514879605133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 257439802565 + 257439802566.
It is an arithmetic number, because the mean of its divisors is an integer number (257439802566).
Almost surely, 2514879605131 is an apocalyptic number.
514879605131 is a deficient number, since it is larger than the sum of its proper divisors (1).
514879605131 is an equidigital number, since it uses as much as digits as its factorization.
514879605131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 907200, while the sum is 50.
The spelling of 514879605131 in words is "five hundred fourteen billion, eight hundred seventy-nine million, six hundred five thousand, one hundred thirty-one".
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