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514879675001 is a prime number
BaseRepresentation
bin1110111111000010011…
…10000101101001111001
31211012222211221112001122
413133201032011221321
531413433144100001
61032311002155025
752125125012126
oct7374116055171
91735884845048
10514879675001
111893a517656a
12839541b2a75
1339725a87cb3
141acc548574d
15d5d70cab1b
hex77e1385a79

514879675001 has 2 divisors, whose sum is σ = 514879675002. Its totient is φ = 514879675000.

The previous prime is 514879674977. The next prime is 514879675003. The reversal of 514879675001 is 100576978415.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 328902250000 + 185977425001 = 573500^2 + 431251^2 .

It is a cyclic number.

It is not a de Polignac number, because 514879675001 - 218 = 514879412857 is a prime.

Together with 514879675003, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (514879675003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 257439837500 + 257439837501.

It is an arithmetic number, because the mean of its divisors is an integer number (257439837501).

Almost surely, 2514879675001 is an apocalyptic number.

It is an amenable number.

514879675001 is a deficient number, since it is larger than the sum of its proper divisors (1).

514879675001 is an equidigital number, since it uses as much as digits as its factorization.

514879675001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2116800, while the sum is 53.

The spelling of 514879675001 in words is "five hundred fourteen billion, eight hundred seventy-nine million, six hundred seventy-five thousand, one".