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51490230997 is a prime number
BaseRepresentation
bin101111111101000011…
…101001001011010101
311220220102221202020111
4233331003221023111
51320422444342442
635353154203021
73501655512352
oct577503511325
9156812852214
1051490230997
111a922990717
129b8bb83471
134b1772160a
1426c660d629
15151560eb17
hexbfd0e92d5

51490230997 has 2 divisors, whose sum is σ = 51490230998. Its totient is φ = 51490230996.

The previous prime is 51490230947. The next prime is 51490231027. The reversal of 51490230997 is 79903209415.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 31910105956 + 19580125041 = 178634^2 + 139929^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51490230997 is a prime.

It is a super-2 number, since 2×514902309972 (a number of 22 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 51490230997.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51490230937) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25745115498 + 25745115499.

It is an arithmetic number, because the mean of its divisors is an integer number (25745115499).

Almost surely, 251490230997 is an apocalyptic number.

It is an amenable number.

51490230997 is a deficient number, since it is larger than the sum of its proper divisors (1).

51490230997 is an equidigital number, since it uses as much as digits as its factorization.

51490230997 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 612360, while the sum is 49.

The spelling of 51490230997 in words is "fifty-one billion, four hundred ninety million, two hundred thirty thousand, nine hundred ninety-seven".