Base | Representation |
---|---|
bin | 100101011110010000111… |
… | …0101101110110010100111 |
3 | 200020100122121222202022111 |
4 | 1022330201311232302213 |
5 | 1133340134240140234 |
6 | 14541552402141451 |
7 | 1041043405423435 |
oct | 112744165566247 |
9 | 20210577882274 |
10 | 5150233521319 |
11 | 1706224613737 |
12 | 6b2196951887 |
13 | 2b4884b36703 |
14 | 13b3b6163d55 |
15 | 8de81a7c664 |
hex | 4af21d6eca7 |
5150233521319 has 2 divisors, whose sum is σ = 5150233521320. Its totient is φ = 5150233521318.
The previous prime is 5150233521313. The next prime is 5150233521383. The reversal of 5150233521319 is 9131253320515.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5150233521319 - 219 = 5150232997031 is a prime.
It is a super-2 number, since 2×51502335213192 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5150233521313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2575116760659 + 2575116760660.
It is an arithmetic number, because the mean of its divisors is an integer number (2575116760660).
Almost surely, 25150233521319 is an apocalyptic number.
5150233521319 is a deficient number, since it is larger than the sum of its proper divisors (1).
5150233521319 is an equidigital number, since it uses as much as digits as its factorization.
5150233521319 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 121500, while the sum is 40.
The spelling of 5150233521319 in words is "five trillion, one hundred fifty billion, two hundred thirty-three million, five hundred twenty-one thousand, three hundred nineteen".
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