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5150255251235 = 51030051050247
BaseRepresentation
bin100101011110010001100…
…1000100111111100100011
3200020100201010212202011012
41022330203020213330203
51133340210321014420
614541554500011135
71041044061216113
oct112744310477443
920210633782135
105150255251235
111706235905746
126b21a2090aab
132b48894a4353
1413b3b8dbd043
158de83920dc5
hex4af23227f23

5150255251235 has 4 divisors (see below), whose sum is σ = 6180306301488. Its totient is φ = 4120204200984.

The previous prime is 5150255251231. The next prime is 5150255251241. The reversal of 5150255251235 is 5321525520515.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5150255251235 - 22 = 5150255251231 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5150255251192 and 5150255251201.

It is not an unprimeable number, because it can be changed into a prime (5150255251231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 515025525119 + ... + 515025525128.

It is an arithmetic number, because the mean of its divisors is an integer number (1545076575372).

Almost surely, 25150255251235 is an apocalyptic number.

5150255251235 is a deficient number, since it is larger than the sum of its proper divisors (1030051050253).

5150255251235 is a wasteful number, since it uses less digits than its factorization.

5150255251235 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1030051050252.

The product of its (nonzero) digits is 375000, while the sum is 41.

The spelling of 5150255251235 in words is "five trillion, one hundred fifty billion, two hundred fifty-five million, two hundred fifty-one thousand, two hundred thirty-five".

Divisors: 1 5 1030051050247 5150255251235