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5151251114113 = 13396250085701
BaseRepresentation
bin100101011110101111001…
…1111100010100010000001
3200020110021112202211012111
41022331132133202202001
51133344230241122423
614542241352455321
71041110543006326
oct112753637424201
920213245684174
105151251114113
1117066a6a63215
126b241b6aa541
132b49b78c3420
1413b471370b4d
158dee108660d
hex4af5e7e2881

5151251114113 has 4 divisors (see below), whose sum is σ = 5547501199828. Its totient is φ = 4755001028400.

The previous prime is 5151251114099. The next prime is 5151251114137. The reversal of 5151251114113 is 3114111521515.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2307093663744 + 2844157450369 = 1518912^2 + 1686463^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5151251114113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5151251114143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 198125042838 + ... + 198125042863.

It is an arithmetic number, because the mean of its divisors is an integer number (1386875299957).

Almost surely, 25151251114113 is an apocalyptic number.

It is an amenable number.

5151251114113 is a deficient number, since it is larger than the sum of its proper divisors (396250085715).

5151251114113 is a wasteful number, since it uses less digits than its factorization.

5151251114113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 396250085714.

The product of its digits is 3000, while the sum is 31.

Adding to 5151251114113 its reverse (3114111521515), we get a palindrome (8265362635628).

The spelling of 5151251114113 in words is "five trillion, one hundred fifty-one billion, two hundred fifty-one million, one hundred fourteen thousand, one hundred thirteen".

Divisors: 1 13 396250085701 5151251114113