Base | Representation |
---|---|
bin | 100101011110110001000… |
… | …1000000010010001100111 |
3 | 200020110102210110021100201 |
4 | 1022331202020002101213 |
5 | 1133344341341432133 |
6 | 14542251411051331 |
7 | 1041112213030534 |
oct | 112754210022147 |
9 | 20213383407321 |
10 | 5151312061543 |
11 | 170672840099a |
12 | 6b2437ba0b47 |
13 | 2b49c74126ab |
14 | 13b4794b7d8b |
15 | 8dee65c4d7d |
hex | 4af62202467 |
5151312061543 has 2 divisors, whose sum is σ = 5151312061544. Its totient is φ = 5151312061542.
The previous prime is 5151312061487. The next prime is 5151312061631. The reversal of 5151312061543 is 3451602131515.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5151312061543 - 213 = 5151312053351 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5151312061243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2575656030771 + 2575656030772.
It is an arithmetic number, because the mean of its divisors is an integer number (2575656030772).
Almost surely, 25151312061543 is an apocalyptic number.
5151312061543 is a deficient number, since it is larger than the sum of its proper divisors (1).
5151312061543 is an equidigital number, since it uses as much as digits as its factorization.
5151312061543 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54000, while the sum is 37.
The spelling of 5151312061543 in words is "five trillion, one hundred fifty-one billion, three hundred twelve million, sixty-one thousand, five hundred forty-three".
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