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51521244133 is a prime number
BaseRepresentation
bin101111111110111001…
…111100101111100101
311220222121022101021011
4233332321330233211
51321003414303013
635400223022221
73502513230562
oct577671745745
9156877271234
1051521244133
111a939443307
129b9a43a971
134b20c8c798
1426ca7a3869
1515181d8c3d
hexbfee7cbe5

51521244133 has 2 divisors, whose sum is σ = 51521244134. Its totient is φ = 51521244132.

The previous prime is 51521244077. The next prime is 51521244163. The reversal of 51521244133 is 33144212515.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 46365716929 + 5155527204 = 215327^2 + 71802^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51521244133 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 51521244095 and 51521244104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51521244163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25760622066 + 25760622067.

It is an arithmetic number, because the mean of its divisors is an integer number (25760622067).

Almost surely, 251521244133 is an apocalyptic number.

It is an amenable number.

51521244133 is a deficient number, since it is larger than the sum of its proper divisors (1).

51521244133 is an equidigital number, since it uses as much as digits as its factorization.

51521244133 is an evil number, because the sum of its binary digits is even.

The product of its digits is 14400, while the sum is 31.

Adding to 51521244133 its reverse (33144212515), we get a palindrome (84665456648).

The spelling of 51521244133 in words is "fifty-one billion, five hundred twenty-one million, two hundred forty-four thousand, one hundred thirty-three".