Base | Representation |
---|---|
bin | 11110101101110… |
… | …000110101101001 |
3 | 1022220122121112201 |
4 | 132231300311221 |
5 | 2023410004001 |
6 | 123044540201 |
7 | 15525042160 |
oct | 3655606551 |
9 | 1286577481 |
10 | 515313001 |
11 | 244976315 |
12 | 1246b1661 |
13 | 829b7048 |
14 | 4c6203d7 |
15 | 30390501 |
hex | 1eb70d69 |
515313001 has 4 divisors (see below), whose sum is σ = 588929152. Its totient is φ = 441696852.
The previous prime is 515312983. The next prime is 515313049. The reversal of 515313001 is 100313515.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 515313001 - 27 = 515312873 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 515313001.
It is not an unprimeable number, because it can be changed into a prime (515313901) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36808065 + ... + 36808078.
It is an arithmetic number, because the mean of its divisors is an integer number (147232288).
Almost surely, 2515313001 is an apocalyptic number.
It is an amenable number.
515313001 is a deficient number, since it is larger than the sum of its proper divisors (73616151).
515313001 is an equidigital number, since it uses as much as digits as its factorization.
515313001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 73616150.
The product of its (nonzero) digits is 225, while the sum is 19.
The square root of 515313001 is about 22700.5066243025. The cubic root of 515313001 is about 801.7218128960.
Adding to 515313001 its reverse (100313515), we get a palindrome (615626516).
The spelling of 515313001 in words is "five hundred fifteen million, three hundred thirteen thousand, one".
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