Base | Representation |
---|---|
bin | 101111111111101000… |
… | …000101111001010001 |
3 | 11221000110001221000011 |
4 | 233333220011321101 |
5 | 1321020013341431 |
6 | 35401334154521 |
7 | 3503021110315 |
oct | 577750057121 |
9 | 157013057004 |
10 | 51533340241 |
11 | 1a945255299 |
12 | 9ba24b2a41 |
13 | 4b23636446 |
14 | 26cc231b45 |
15 | 15192c7cb1 |
hex | bffa05e51 |
51533340241 has 4 divisors (see below), whose sum is σ = 51533928432. Its totient is φ = 51532752052.
The previous prime is 51533340233. The next prime is 51533340259. The reversal of 51533340241 is 14204333515.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 14204333515 = 5 ⋅2840866703.
It is a cyclic number.
It is not a de Polignac number, because 51533340241 - 23 = 51533340233 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (51533341241) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 133411 + ... + 347656.
It is an arithmetic number, because the mean of its divisors is an integer number (12883482108).
Almost surely, 251533340241 is an apocalyptic number.
It is an amenable number.
51533340241 is a deficient number, since it is larger than the sum of its proper divisors (588191).
51533340241 is a wasteful number, since it uses less digits than its factorization.
51533340241 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 588190.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 51533340241 its reverse (14204333515), we get a palindrome (65737673756).
The spelling of 51533340241 in words is "fifty-one billion, five hundred thirty-three million, three hundred forty thousand, two hundred forty-one".
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