Base | Representation |
---|---|
bin | 100101100000000111110… |
… | …1000111010110111010111 |
3 | 200020201221200011101200212 |
4 | 1023000033220322313113 |
5 | 1133421322110442221 |
6 | 14543452321400035 |
7 | 1041244311552620 |
oct | 113001750726727 |
9 | 20221850141625 |
10 | 5154223140311 |
11 | 1707991657513 |
12 | 6b2b0aa9901b |
13 | 2b506c561ccb |
14 | 13b673d74a47 |
15 | 8e116e51b5b |
hex | 4b00fa3add7 |
5154223140311 has 16 divisors (see below), whose sum is σ = 5922310464000. Its totient is φ = 4394133096288.
The previous prime is 5154223140281. The next prime is 5154223140317. The reversal of 5154223140311 is 1130413224515.
It is a cyclic number.
It is not a de Polignac number, because 5154223140311 - 210 = 5154223139287 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5154223140317) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1156925 + ... + 3412758.
It is an arithmetic number, because the mean of its divisors is an integer number (370144404000).
Almost surely, 25154223140311 is an apocalyptic number.
5154223140311 is a deficient number, since it is larger than the sum of its proper divisors (768087323689).
5154223140311 is a wasteful number, since it uses less digits than its factorization.
5154223140311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4570558.
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 5154223140311 its reverse (1130413224515), we get a palindrome (6284636364826).
The spelling of 5154223140311 in words is "five trillion, one hundred fifty-four billion, two hundred twenty-three million, one hundred forty thousand, three hundred eleven".
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