Base | Representation |
---|---|
bin | 110000000000110011… |
… | …000011011101110101 |
3 | 11221001211001021220111 |
4 | 300000303003131311 |
5 | 1321040031203333 |
6 | 35403315303021 |
7 | 3503350123402 |
oct | 600063033565 |
9 | 157054037814 |
10 | 51552991093 |
11 | 1a95535726a |
12 | 9ba8baaa71 |
13 | 4b27726976 |
14 | 26d0aa92a9 |
15 | 151adaa4cd |
hex | c00cc3775 |
51552991093 has 2 divisors, whose sum is σ = 51552991094. Its totient is φ = 51552991092.
The previous prime is 51552991033. The next prime is 51552991109. The reversal of 51552991093 is 39019925515.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 51398784369 + 154206724 = 226713^2 + 12418^2 .
It is a cyclic number.
It is not a de Polignac number, because 51552991093 - 29 = 51552990581 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51552991033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25776495546 + 25776495547.
It is an arithmetic number, because the mean of its divisors is an integer number (25776495547).
Almost surely, 251552991093 is an apocalyptic number.
It is an amenable number.
51552991093 is a deficient number, since it is larger than the sum of its proper divisors (1).
51552991093 is an equidigital number, since it uses as much as digits as its factorization.
51552991093 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 546750, while the sum is 49.
The spelling of 51552991093 in words is "fifty-one billion, five hundred fifty-two million, nine hundred ninety-one thousand, ninety-three".
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