Base | Representation |
---|---|
bin | 110000000000111010… |
… | …101110011100011111 |
3 | 11221001221211110112211 |
4 | 300000322232130133 |
5 | 1321041040032033 |
6 | 35403430341251 |
7 | 3503403200461 |
oct | 600072563437 |
9 | 157057743484 |
10 | 51555002143 |
11 | 1a956500197 |
12 | 9ba97ba827 |
13 | 4b27c7c138 |
14 | 26d1070131 |
15 | 151b1562cd |
hex | c00eae71f |
51555002143 has 4 divisors (see below), whose sum is σ = 52134271920. Its totient is φ = 50975732368.
The previous prime is 51555002131. The next prime is 51555002183. The reversal of 51555002143 is 34120055515.
51555002143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51555002143 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51555002183) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 289634755 + ... + 289634932.
It is an arithmetic number, because the mean of its divisors is an integer number (13033567980).
Almost surely, 251555002143 is an apocalyptic number.
51555002143 is a deficient number, since it is larger than the sum of its proper divisors (579269777).
51555002143 is an equidigital number, since it uses as much as digits as its factorization.
51555002143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 579269776.
The product of its (nonzero) digits is 15000, while the sum is 31.
Adding to 51555002143 its reverse (34120055515), we get a palindrome (85675057658).
The spelling of 51555002143 in words is "fifty-one billion, five hundred fifty-five million, two thousand, one hundred forty-three".
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