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51555002143 = 89579269687
BaseRepresentation
bin110000000000111010…
…101110011100011111
311221001221211110112211
4300000322232130133
51321041040032033
635403430341251
73503403200461
oct600072563437
9157057743484
1051555002143
111a956500197
129ba97ba827
134b27c7c138
1426d1070131
15151b1562cd
hexc00eae71f

51555002143 has 4 divisors (see below), whose sum is σ = 52134271920. Its totient is φ = 50975732368.

The previous prime is 51555002131. The next prime is 51555002183. The reversal of 51555002143 is 34120055515.

51555002143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51555002143 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (51555002183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 289634755 + ... + 289634932.

It is an arithmetic number, because the mean of its divisors is an integer number (13033567980).

Almost surely, 251555002143 is an apocalyptic number.

51555002143 is a deficient number, since it is larger than the sum of its proper divisors (579269777).

51555002143 is an equidigital number, since it uses as much as digits as its factorization.

51555002143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 579269776.

The product of its (nonzero) digits is 15000, while the sum is 31.

Adding to 51555002143 its reverse (34120055515), we get a palindrome (85675057658).

The spelling of 51555002143 in words is "fifty-one billion, five hundred fifty-five million, two thousand, one hundred forty-three".

Divisors: 1 89 579269687 51555002143