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5156521042132 = 221289130260533
BaseRepresentation
bin100101100001001100010…
…0110101110000011010100
3200020221212211001220101201
41023002120212232003110
51133441023341322012
614544512325402244
71041355253445055
oct113023046560324
920227784056351
105156521042132
111708960775129
126b3450569384
132b5347651125
1413b81121872c
158e1eda5b857
hex4b0989ae0d4

5156521042132 has 6 divisors (see below), whose sum is σ = 9023911823738. Its totient is φ = 2578260521064.

The previous prime is 5156521042063. The next prime is 5156521042199. The reversal of 5156521042132 is 2312401256515.

It can be written as a sum of positive squares in only one way, i.e., 2799049457296 + 2357471584836 = 1673036^2 + 1535406^2 .

It is a junction number, because it is equal to n+sod(n) for n = 5156521042091 and 5156521042100.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 644565130263 + ... + 644565130270.

Almost surely, 25156521042132 is an apocalyptic number.

It is an amenable number.

5156521042132 is a deficient number, since it is larger than the sum of its proper divisors (3867390781606).

5156521042132 is a wasteful number, since it uses less digits than its factorization.

5156521042132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1289130260537 (or 1289130260535 counting only the distinct ones).

The product of its (nonzero) digits is 72000, while the sum is 37.

Adding to 5156521042132 its reverse (2312401256515), we get a palindrome (7468922298647).

The spelling of 5156521042132 in words is "five trillion, one hundred fifty-six billion, five hundred twenty-one million, forty-two thousand, one hundred thirty-two".

Divisors: 1 2 4 1289130260533 2578260521066 5156521042132