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51566000314441 is a prime number
BaseRepresentation
bin10111011100110001001010…
…01000011001100001001001
320202120122212020000202121211
423232120211020121201021
523224324132040030231
6301401032110533121
713601343362442364
oct1356304510314111
9222518766022554
1051566000314441
1115481021944598
125949a052071a1
1322a0864742682
14ca3b445b90db
155e653b407eb1
hex2ee625219849

51566000314441 has 2 divisors, whose sum is σ = 51566000314442. Its totient is φ = 51566000314440.

The previous prime is 51566000314429. The next prime is 51566000314481. The reversal of 51566000314441 is 14441300066515.

It is an a-pointer prime, because the next prime (51566000314481) can be obtained adding 51566000314441 to its sum of digits (40).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 49041714874441 + 2524285440000 = 7002979^2 + 1588800^2 .

It is a cyclic number.

It is not a de Polignac number, because 51566000314441 - 221 = 51565998217289 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 51566000314394 and 51566000314403.

It is not a weakly prime, because it can be changed into another prime (51566000314421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25783000157220 + 25783000157221.

It is an arithmetic number, because the mean of its divisors is an integer number (25783000157221).

Almost surely, 251566000314441 is an apocalyptic number.

It is an amenable number.

51566000314441 is a deficient number, since it is larger than the sum of its proper divisors (1).

51566000314441 is an equidigital number, since it uses as much as digits as its factorization.

51566000314441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 172800, while the sum is 40.

The spelling of 51566000314441 in words is "fifty-one trillion, five hundred sixty-six billion, three hundred fourteen thousand, four hundred forty-one".