Base | Representation |
---|---|
bin | 110000000011010101… |
… | …101111111101110101 |
3 | 11221011210022010011022 |
4 | 300003111233331311 |
5 | 1321131441000233 |
6 | 35411441350525 |
7 | 3504405465302 |
oct | 600325577565 |
9 | 157153263138 |
10 | 51595640693 |
11 | 1a977437573 |
12 | 9bbb338445 |
13 | 4b3350a50c |
14 | 26d660c0a9 |
15 | 151e9d2398 |
hex | c0356ff75 |
51595640693 has 2 divisors, whose sum is σ = 51595640694. Its totient is φ = 51595640692.
The previous prime is 51595640687. The next prime is 51595640711. The reversal of 51595640693 is 39604659515.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 37738113169 + 13857527524 = 194263^2 + 117718^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51595640693 is a prime.
It is a super-2 number, since 2×515956406932 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51595645693) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25797820346 + 25797820347.
It is an arithmetic number, because the mean of its divisors is an integer number (25797820347).
Almost surely, 251595640693 is an apocalyptic number.
It is an amenable number.
51595640693 is a deficient number, since it is larger than the sum of its proper divisors (1).
51595640693 is an equidigital number, since it uses as much as digits as its factorization.
51595640693 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4374000, while the sum is 53.
The spelling of 51595640693 in words is "fifty-one billion, five hundred ninety-five million, six hundred forty thousand, six hundred ninety-three".
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