Base | Representation |
---|---|
bin | 100101100011001001100… |
… | …1101101101011101001111 |
3 | 200021100201211121220122111 |
4 | 1023012103031231131033 |
5 | 1134023131221123221 |
6 | 14550445443124451 |
7 | 1041564406354006 |
oct | 113062315553517 |
9 | 20240654556574 |
10 | 5160725567311 |
11 | 170a719052126 |
12 | 6b4224673727 |
13 | 2b5867752752 |
14 | 13bacd7abc3d |
15 | 8e397c31be1 |
hex | 4b19336d74f |
5160725567311 has 2 divisors, whose sum is σ = 5160725567312. Its totient is φ = 5160725567310.
The previous prime is 5160725567279. The next prime is 5160725567351. The reversal of 5160725567311 is 1137655270615.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5160725567311 - 25 = 5160725567279 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5160725567351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2580362783655 + 2580362783656.
It is an arithmetic number, because the mean of its divisors is an integer number (2580362783656).
Almost surely, 25160725567311 is an apocalyptic number.
5160725567311 is a deficient number, since it is larger than the sum of its proper divisors (1).
5160725567311 is an equidigital number, since it uses as much as digits as its factorization.
5160725567311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1323000, while the sum is 49.
The spelling of 5160725567311 in words is "five trillion, one hundred sixty billion, seven hundred twenty-five million, five hundred sixty-seven thousand, three hundred eleven".
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