Base | Representation |
---|---|
bin | 110000000100011001… |
… | …011011001001111111 |
3 | 11221020000200102121212 |
4 | 300010121123021333 |
5 | 1321201011144442 |
6 | 35413313515035 |
7 | 3505012334111 |
oct | 600431331177 |
9 | 157200612555 |
10 | 51613381247 |
11 | 1a98645428a |
12 | a005272a7b |
13 | 4b370ac39c |
14 | 26d8b093b1 |
15 | 1521338a82 |
hex | c0465b27f |
51613381247 has 4 divisors (see below), whose sum is σ = 51621230616. Its totient is φ = 51605531880.
The previous prime is 51613381217. The next prime is 51613381271. The reversal of 51613381247 is 74218331615.
51613381247 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 51613381247 - 210 = 51613380223 is a prime.
It is a super-2 number, since 2×516133812472 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51613381217) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3914813 + ... + 3927974.
It is an arithmetic number, because the mean of its divisors is an integer number (12905307654).
Almost surely, 251613381247 is an apocalyptic number.
51613381247 is a deficient number, since it is larger than the sum of its proper divisors (7849369).
51613381247 is an equidigital number, since it uses as much as digits as its factorization.
51613381247 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7849368.
The product of its digits is 120960, while the sum is 41.
The spelling of 51613381247 in words is "fifty-one billion, six hundred thirteen million, three hundred eighty-one thousand, two hundred forty-seven".
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