Base | Representation |
---|---|
bin | 11110110001101… |
… | …001010100101101 |
3 | 1022222120022200212 |
4 | 132301221110231 |
5 | 2024140041142 |
6 | 123122432205 |
7 | 15536511413 |
oct | 3661512455 |
9 | 1288508625 |
10 | 516330797 |
11 | 245500a74 |
12 | 124b02665 |
13 | 82c823a8 |
14 | 4c8072b3 |
15 | 304e1d82 |
hex | 1ec6952d |
516330797 has 2 divisors, whose sum is σ = 516330798. Its totient is φ = 516330796.
The previous prime is 516330781. The next prime is 516330821. The reversal of 516330797 is 797033615.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 481626916 + 34703881 = 21946^2 + 5891^2 .
It is a cyclic number.
It is not a de Polignac number, because 516330797 - 24 = 516330781 is a prime.
It is equal to p27169538 and since 516330797 and 27169538 have the same sum of digits, it is a Honaker prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (516332797) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 258165398 + 258165399.
It is an arithmetic number, because the mean of its divisors is an integer number (258165399).
Almost surely, 2516330797 is an apocalyptic number.
It is an amenable number.
516330797 is a deficient number, since it is larger than the sum of its proper divisors (1).
516330797 is an equidigital number, since it uses as much as digits as its factorization.
516330797 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 119070, while the sum is 41.
The square root of 516330797 is about 22722.9134795695. The cubic root of 516330797 is about 802.2492933597.
The spelling of 516330797 in words is "five hundred sixteen million, three hundred thirty thousand, seven hundred ninety-seven".
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