Base | Representation |
---|---|
bin | 1111000010000000011… |
… | …11100011111110100111 |
3 | 1211101002221202101100002 |
4 | 13201000033203332213 |
5 | 31430214304144441 |
6 | 1033133112011515 |
7 | 52212463455242 |
oct | 7410017437647 |
9 | 1741087671302 |
10 | 516473896871 |
11 | 18a043060aa9 |
12 | 8411a090b9b |
13 | 3991b149a4a |
14 | 1add70b4259 |
15 | d67c037b9b |
hex | 78403e3fa7 |
516473896871 has 16 divisors (see below), whose sum is σ = 557405600544. Its totient is φ = 476722182144.
The previous prime is 516473896859. The next prime is 516473896903. The reversal of 516473896871 is 178698374615.
It is a cyclic number.
It is not a de Polignac number, because 516473896871 - 238 = 241595989927 is a prime.
It is a super-2 number, since 2×5164738968712 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 516473896798 and 516473896807.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (516473896801) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2059136 + ... + 2296298.
It is an arithmetic number, because the mean of its divisors is an integer number (34837850034).
Almost surely, 2516473896871 is an apocalyptic number.
516473896871 is a deficient number, since it is larger than the sum of its proper divisors (40931703673).
516473896871 is a wasteful number, since it uses less digits than its factorization.
516473896871 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 239650.
The product of its digits is 60963840, while the sum is 65.
The spelling of 516473896871 in words is "five hundred sixteen billion, four hundred seventy-three million, eight hundred ninety-six thousand, eight hundred seventy-one".
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