Base | Representation |
---|---|
bin | 100101100101011011010… |
… | …0010100100110111101001 |
3 | 200021211100110120201212022 |
4 | 1023022312202210313221 |
5 | 1134113133440111032 |
6 | 14553014442154225 |
7 | 1042126465536314 |
oct | 113126642446751 |
9 | 20254313521768 |
10 | 5165613207017 |
11 | 17117a6a9618a |
12 | 6b51694b2975 |
13 | 2b6166230853 |
14 | 13c03498197b |
15 | 8e581d91512 |
hex | 4b2b68a4de9 |
5165613207017 has 8 divisors (see below), whose sum is σ = 5239923102624. Its totient is φ = 5091590778048.
The previous prime is 5165613206989. The next prime is 5165613207031. The reversal of 5165613207017 is 7107023165615.
It is a happy number.
5165613207017 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5165613207017 - 210 = 5165613205993 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5165613201017) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 71830463 + ... + 71902340.
It is an arithmetic number, because the mean of its divisors is an integer number (654990387828).
Almost surely, 25165613207017 is an apocalyptic number.
It is an amenable number.
5165613207017 is a deficient number, since it is larger than the sum of its proper divisors (74309895607).
5165613207017 is a wasteful number, since it uses less digits than its factorization.
5165613207017 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 143733319.
The product of its (nonzero) digits is 264600, while the sum is 44.
The spelling of 5165613207017 in words is "five trillion, one hundred sixty-five billion, six hundred thirteen million, two hundred seven thousand, seventeen".
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