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516663255049771 is a prime number
BaseRepresentation
bin111010101111001110000100…
…1110010010010011000101011
32111202100112011120201222020111
41311132130021302102120223
51020210002321243043041
65030503453411235151
7213553455051045214
oct16536341162223053
92452315146658214
10516663255049771
1113a696724101975
1249b449728a8ab7
131923a19c73ac1b
1491828c650a40b
153eae8e4a1d981
hex1d5e709c9262b

516663255049771 has 2 divisors, whose sum is σ = 516663255049772. Its totient is φ = 516663255049770.

The previous prime is 516663255049751. The next prime is 516663255049789. The reversal of 516663255049771 is 177940552366615.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 516663255049771 - 215 = 516663255017003 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 516663255049697 and 516663255049706.

It is not a weakly prime, because it can be changed into another prime (516663255049751) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 258331627524885 + 258331627524886.

It is an arithmetic number, because the mean of its divisors is an integer number (258331627524886).

Almost surely, 2516663255049771 is an apocalyptic number.

516663255049771 is a deficient number, since it is larger than the sum of its proper divisors (1).

516663255049771 is an equidigital number, since it uses as much as digits as its factorization.

516663255049771 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 285768000, while the sum is 67.

The spelling of 516663255049771 in words is "five hundred sixteen trillion, six hundred sixty-three billion, two hundred fifty-five million, forty-nine thousand, seven hundred seventy-one".