Base | Representation |
---|---|
bin | 111010101111001110000100… |
… | …1110010010010011000111101 |
3 | 2111202100112011120201222021011 |
4 | 1311132130021302102120331 |
5 | 1020210002321243043124 |
6 | 5030503453411235221 |
7 | 213553455051045241 |
oct | 16536341162223075 |
9 | 2452315146658234 |
10 | 516663255049789 |
11 | 13a696724101991 |
12 | 49b449728a8b11 |
13 | 1923a19c73ac33 |
14 | 91828c650a421 |
15 | 3eae8e4a1d994 |
hex | 1d5e709c9263d |
516663255049789 has 2 divisors, whose sum is σ = 516663255049790. Its totient is φ = 516663255049788.
The previous prime is 516663255049771. The next prime is 516663255049829. The reversal of 516663255049789 is 987940552366615.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 496788733182564 + 19874521867225 = 22288758^2 + 4458085^2 .
It is a cyclic number.
It is not a de Polignac number, because 516663255049789 - 27 = 516663255049661 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (516663255059789) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 258331627524894 + 258331627524895.
It is an arithmetic number, because the mean of its divisors is an integer number (258331627524895).
It is a 1-persistent number, because it is pandigital, but 2⋅516663255049789 = 1033326510099578 is not.
Almost surely, 2516663255049789 is an apocalyptic number.
It is an amenable number.
516663255049789 is a deficient number, since it is larger than the sum of its proper divisors (1).
516663255049789 is an equidigital number, since it uses as much as digits as its factorization.
516663255049789 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2939328000, while the sum is 76.
The spelling of 516663255049789 in words is "five hundred sixteen trillion, six hundred sixty-three billion, two hundred fifty-five million, forty-nine thousand, seven hundred eighty-nine".
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