Base | Representation |
---|---|
bin | 11110110100000… |
… | …101110111101101 |
3 | 1100000202220021121 |
4 | 132310011313231 |
5 | 2024321101023 |
6 | 123144300541 |
7 | 15545122015 |
oct | 3664056755 |
9 | 1300686247 |
10 | 516972013 |
11 | 2458a97a8 |
12 | 125171751 |
13 | 831481cc |
14 | 4c932c45 |
15 | 305bbd5d |
hex | 1ed05ded |
516972013 has 2 divisors, whose sum is σ = 516972014. Its totient is φ = 516972012.
The previous prime is 516971977. The next prime is 516972031. The reversal of 516972013 is 310279615.
Together with next prime (516972031) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 258502084 + 258469929 = 16078^2 + 16077^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-516972013 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 516972013.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (516972913) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 258486006 + 258486007.
It is an arithmetic number, because the mean of its divisors is an integer number (258486007).
Almost surely, 2516972013 is an apocalyptic number.
516972013 is the 16078-th centered square number.
It is an amenable number.
516972013 is a deficient number, since it is larger than the sum of its proper divisors (1).
516972013 is an equidigital number, since it uses as much as digits as its factorization.
516972013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11340, while the sum is 34.
The square root of 516972013 is about 22737.0185600487. The cubic root of 516972013 is about 802.5812525656.
The spelling of 516972013 in words is "five hundred sixteen million, nine hundred seventy-two thousand, thirteen".
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