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517216216450247 = 3103316666652159
BaseRepresentation
bin111010110011001111100100…
…0110110101000010011000111
32111211022101110102011120211222
41311212133020312220103013
51020243032302402401442
65032005503305150555
7213641432001310136
oct16546371066502307
92454271412146758
10517216216450247
1113a88a190429426
124a013b7448b45b
131927a384016992
1491a158149991d
153ebdea9eb38d2
hex1d667c8da84c7

517216216450247 has 4 divisors (see below), whose sum is σ = 517232883133440. Its totient is φ = 517199549767056.

The previous prime is 517216216450237. The next prime is 517216216450249. The reversal of 517216216450247 is 742054612612715.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 517216216450247 - 220 = 517216215401671 is a prime.

It is a super-2 number, since 2×5172162164502472 (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (517216216450249) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8333295047 + ... + 8333357112.

It is an arithmetic number, because the mean of its divisors is an integer number (129308220783360).

Almost surely, 2517216216450247 is an apocalyptic number.

517216216450247 is a deficient number, since it is larger than the sum of its proper divisors (16666683193).

517216216450247 is a wasteful number, since it uses less digits than its factorization.

517216216450247 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16666683192.

The product of its (nonzero) digits is 5644800, while the sum is 53.

The spelling of 517216216450247 in words is "five hundred seventeen trillion, two hundred sixteen billion, two hundred sixteen million, four hundred fifty thousand, two hundred forty-seven".

Divisors: 1 31033 16666652159 517216216450247