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5175013903 is a prime number
BaseRepresentation
bin1001101000111010…
…00111001000001111
3111100122200221111121
410310131013020033
541044300421103
62213302301411
7242145615043
oct46435071017
914318627447
105175013903
1122161845a4
121005127867
136461a8107
1437141c023
152044c76bd
hex13474720f

5175013903 has 2 divisors, whose sum is σ = 5175013904. Its totient is φ = 5175013902.

The previous prime is 5175013889. The next prime is 5175013919. The reversal of 5175013903 is 3093105715.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 5175013903 - 217 = 5174882831 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5175013933) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2587506951 + 2587506952.

It is an arithmetic number, because the mean of its divisors is an integer number (2587506952).

Almost surely, 25175013903 is an apocalyptic number.

5175013903 is a deficient number, since it is larger than the sum of its proper divisors (1).

5175013903 is an equidigital number, since it uses as much as digits as its factorization.

5175013903 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14175, while the sum is 34.

The square root of 5175013903 is about 71937.5694821558. The cubic root of 5175013903 is about 1729.6988909828.

The spelling of 5175013903 in words is "five billion, one hundred seventy-five million, thirteen thousand, nine hundred three".