Base | Representation |
---|---|
bin | 110000001110001010… |
… | …010101111101100101 |
3 | 11221122102221021200002 |
4 | 300032022111331211 |
5 | 1322014430344343 |
6 | 35441445031045 |
7 | 3512041636532 |
oct | 601612257545 |
9 | 157572837602 |
10 | 51777199973 |
11 | 1aa5a974764 |
12 | a0500b5485 |
13 | 4b62009045 |
14 | 271278dd89 |
15 | 15308e78b8 |
hex | c0e295f65 |
51777199973 has 2 divisors, whose sum is σ = 51777199974. Its totient is φ = 51777199972.
The previous prime is 51777199951. The next prime is 51777199987. The reversal of 51777199973 is 37999177715.
51777199973 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 48392520289 + 3384679684 = 219983^2 + 58178^2 .
It is a cyclic number.
It is not a de Polignac number, because 51777199973 - 26 = 51777199909 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51777199993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25888599986 + 25888599987.
It is an arithmetic number, because the mean of its divisors is an integer number (25888599987).
Almost surely, 251777199973 is an apocalyptic number.
It is an amenable number.
51777199973 is a deficient number, since it is larger than the sum of its proper divisors (1).
51777199973 is an equidigital number, since it uses as much as digits as its factorization.
51777199973 is an evil number, because the sum of its binary digits is even.
The product of its digits is 26254935, while the sum is 65.
The spelling of 51777199973 in words is "fifty-one billion, seven hundred seventy-seven million, one hundred ninety-nine thousand, nine hundred seventy-three".
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