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5180529454117 = 19972594155961
BaseRepresentation
bin100101101100010111110…
…0111100010110000100101
3200100020212000010121011121
41023120233213202300211
51134334211020012432
615003522525133541
71043165230542223
oct113305747426045
920306760117147
105180529454117
111718060903426
126b80309ba2b1
132b76a2604274
1413ca4ba03b13
158eb56660197
hex4b62f9e2c25

5180529454117 has 4 divisors (see below), whose sum is σ = 5183123612076. Its totient is φ = 5177935296160.

The previous prime is 5180529454063. The next prime is 5180529454141. The reversal of 5180529454117 is 7114549250815.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 904108115716 + 4276421338401 = 950846^2 + 2067951^2 .

It is a cyclic number.

It is not a de Polignac number, because 5180529454117 - 231 = 5178381970469 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5180529454187) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1297075984 + ... + 1297079977.

It is an arithmetic number, because the mean of its divisors is an integer number (1295780903019).

Almost surely, 25180529454117 is an apocalyptic number.

It is an amenable number.

5180529454117 is a deficient number, since it is larger than the sum of its proper divisors (2594157959).

5180529454117 is a wasteful number, since it uses less digits than its factorization.

5180529454117 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2594157958.

The product of its (nonzero) digits is 2016000, while the sum is 52.

The spelling of 5180529454117 in words is "five trillion, one hundred eighty billion, five hundred twenty-nine million, four hundred fifty-four thousand, one hundred seventeen".

Divisors: 1 1997 2594155961 5180529454117