Base | Representation |
---|---|
bin | 100101101101001000101… |
… | …1001100001100000010101 |
3 | 200100102002100000020011011 |
4 | 1023122101121201200111 |
5 | 1134401041001234013 |
6 | 15004353410412221 |
7 | 1043254000516615 |
oct | 113322131414025 |
9 | 20312070006134 |
10 | 5182169946133 |
11 | 1718822921354 |
12 | 6b840a291071 |
13 | 2b78a44467bb |
14 | 13cb65838a45 |
15 | 8ec006abc3d |
hex | 4b691661815 |
5182169946133 has 2 divisors, whose sum is σ = 5182169946134. Its totient is φ = 5182169946132.
The previous prime is 5182169946073. The next prime is 5182169946143. The reversal of 5182169946133 is 3316499612815.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4956224682564 + 225945263569 = 2226258^2 + 475337^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5182169946133 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5182169946143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2591084973066 + 2591084973067.
It is an arithmetic number, because the mean of its divisors is an integer number (2591084973067).
Almost surely, 25182169946133 is an apocalyptic number.
It is an amenable number.
5182169946133 is a deficient number, since it is larger than the sum of its proper divisors (1).
5182169946133 is an equidigital number, since it uses as much as digits as its factorization.
5182169946133 is an evil number, because the sum of its binary digits is even.
The product of its digits is 8398080, while the sum is 58.
The spelling of 5182169946133 in words is "five trillion, one hundred eighty-two billion, one hundred sixty-nine million, nine hundred forty-six thousand, one hundred thirty-three".
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