Base | Representation |
---|---|
bin | 110000010001010111… |
… | …100100110101010001 |
3 | 11221210012011121222112 |
4 | 300101113210311101 |
5 | 1322122214003101 |
6 | 35451050115105 |
7 | 3513264143225 |
oct | 602127446521 |
9 | 157705147875 |
10 | 51831000401 |
11 | 1aa88280824 |
12 | a06611ba95 |
13 | 4b701c520b |
14 | 2719996785 |
15 | 15354c36bb |
hex | c115e4d51 |
51831000401 has 2 divisors, whose sum is σ = 51831000402. Its totient is φ = 51831000400.
The previous prime is 51831000367. The next prime is 51831000437. The reversal of 51831000401 is 10400013815.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 40080440401 + 11750560000 = 200201^2 + 108400^2 .
It is a cyclic number.
It is not a de Polignac number, because 51831000401 - 230 = 50757258577 is a prime.
It is not a weakly prime, because it can be changed into another prime (51831000301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25915500200 + 25915500201.
It is an arithmetic number, because the mean of its divisors is an integer number (25915500201).
Almost surely, 251831000401 is an apocalyptic number.
It is an amenable number.
51831000401 is a deficient number, since it is larger than the sum of its proper divisors (1).
51831000401 is an equidigital number, since it uses as much as digits as its factorization.
51831000401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 480, while the sum is 23.
The spelling of 51831000401 in words is "fifty-one billion, eight hundred thirty-one million, four hundred one", and thus it is an aban number.
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