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5188417114703 = 46311206084481
BaseRepresentation
bin100101110000000010111…
…0000100101001001001111
3200101000012201011021100212
41023200011300211021033
51140001334240132303
615011305333113035
71043564545545224
oct113400560451117
920330181137325
105188417114703
111720439221589
126b967248877b
132b835b7a3254
1413d1993c794b
158ee68d69ad8
hex4b805c2524f

5188417114703 has 4 divisors (see below), whose sum is σ = 5199623199648. Its totient is φ = 5177211029760.

The previous prime is 5188417114663. The next prime is 5188417114709. The reversal of 5188417114703 is 3074117148815.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5188417114703 - 230 = 5187343372879 is a prime.

It is a super-2 number, since 2×51884171147032 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5188417114709) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5603041778 + ... + 5603042703.

It is an arithmetic number, because the mean of its divisors is an integer number (1299905799912).

Almost surely, 25188417114703 is an apocalyptic number.

5188417114703 is a deficient number, since it is larger than the sum of its proper divisors (11206084945).

5188417114703 is a wasteful number, since it uses less digits than its factorization.

5188417114703 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11206084944.

The product of its (nonzero) digits is 752640, while the sum is 50.

The spelling of 5188417114703 in words is "five trillion, one hundred eighty-eight billion, four hundred seventeen million, one hundred fourteen thousand, seven hundred three".

Divisors: 1 463 11206084481 5188417114703