Base | Representation |
---|---|
bin | 100101110000000010111… |
… | …0000100101001001001111 |
3 | 200101000012201011021100212 |
4 | 1023200011300211021033 |
5 | 1140001334240132303 |
6 | 15011305333113035 |
7 | 1043564545545224 |
oct | 113400560451117 |
9 | 20330181137325 |
10 | 5188417114703 |
11 | 1720439221589 |
12 | 6b967248877b |
13 | 2b835b7a3254 |
14 | 13d1993c794b |
15 | 8ee68d69ad8 |
hex | 4b805c2524f |
5188417114703 has 4 divisors (see below), whose sum is σ = 5199623199648. Its totient is φ = 5177211029760.
The previous prime is 5188417114663. The next prime is 5188417114709. The reversal of 5188417114703 is 3074117148815.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5188417114703 - 230 = 5187343372879 is a prime.
It is a super-2 number, since 2×51884171147032 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5188417114709) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5603041778 + ... + 5603042703.
It is an arithmetic number, because the mean of its divisors is an integer number (1299905799912).
Almost surely, 25188417114703 is an apocalyptic number.
5188417114703 is a deficient number, since it is larger than the sum of its proper divisors (11206084945).
5188417114703 is a wasteful number, since it uses less digits than its factorization.
5188417114703 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11206084944.
The product of its (nonzero) digits is 752640, while the sum is 50.
The spelling of 5188417114703 in words is "five trillion, one hundred eighty-eight billion, four hundred seventeen million, one hundred fourteen thousand, seven hundred three".
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