Base | Representation |
---|---|
bin | 10111101001010001001010… |
… | …10101110011111000100101 |
3 | 20211002201110211111212122122 |
4 | 23310220211111303320211 |
5 | 23303343241120404114 |
6 | 302330223031435325 |
7 | 13644356655340064 |
oct | 1364504525637045 |
9 | 224081424455578 |
10 | 51995500559909 |
11 | 15627193600a45 |
12 | 59b90abb25b45 |
13 | 2302201a4865a |
14 | cba84a6961db |
15 | 6027c7b0ee8e |
hex | 2f4a25573e25 |
51995500559909 has 2 divisors, whose sum is σ = 51995500559910. Its totient is φ = 51995500559908.
The previous prime is 51995500559869. The next prime is 51995500559923. The reversal of 51995500559909 is 90995500559915.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 49883355724225 + 2112144835684 = 7062815^2 + 1453322^2 .
It is a cyclic number.
It is not a de Polignac number, because 51995500559909 - 212 = 51995500555813 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51995500559999) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25997750279954 + 25997750279955.
It is an arithmetic number, because the mean of its divisors is an integer number (25997750279955).
Almost surely, 251995500559909 is an apocalyptic number.
It is an amenable number.
51995500559909 is a deficient number, since it is larger than the sum of its proper divisors (1).
51995500559909 is an equidigital number, since it uses as much as digits as its factorization.
51995500559909 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 184528125, while the sum is 71.
The spelling of 51995500559909 in words is "fifty-one trillion, nine hundred ninety-five billion, five hundred million, five hundred fifty-nine thousand, nine hundred nine".
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