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52012113 = 339434397
BaseRepresentation
bin1100011001101…
…0010001010001
310121212111012120
43012122101101
5101303341423
65054444453
71201044546
oct306322121
9117774176
1052012113
11273a551a
1215503729
13aa111ca
146c9cbcd
154875ee3
hex319a451

52012113 has 8 divisors (see below), whose sum is σ = 69382848. Its totient is φ = 34658064.

The previous prime is 52012111. The next prime is 52012117. The reversal of 52012113 is 31121025.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 52012113 - 21 = 52012111 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 52012092 and 52012101.

It is not an unprimeable number, because it can be changed into a prime (52012111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9631 + ... + 14027.

It is an arithmetic number, because the mean of its divisors is an integer number (8672856).

Almost surely, 252012113 is an apocalyptic number.

It is an amenable number.

52012113 is a deficient number, since it is larger than the sum of its proper divisors (17370735).

52012113 is a wasteful number, since it uses less digits than its factorization.

52012113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8343.

The product of its (nonzero) digits is 60, while the sum is 15.

The square root of 52012113 is about 7211.9423874571. The cubic root of 52012113 is about 373.2800954237.

Adding to 52012113 its reverse (31121025), we get a palindrome (83133138).

It can be divided in two parts, 52012 and 113, that added together give a palindrome (52125).

The spelling of 52012113 in words is "fifty-two million, twelve thousand, one hundred thirteen".

Divisors: 1 3 3943 4397 11829 13191 17337371 52012113