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52013251207 is a prime number
BaseRepresentation
bin110000011100001110…
…110011101010000111
311222020220002221002101
4300130032303222013
51323010343014312
635521120252531
73520636224541
oct603416635207
9158226087071
1052013251207
1120071140525
12a0b7171147
134b9bba6728
142735c78691
1515464c3a57
hexc1c3b3a87

52013251207 has 2 divisors, whose sum is σ = 52013251208. Its totient is φ = 52013251206.

The previous prime is 52013251183. The next prime is 52013251229. The reversal of 52013251207 is 70215231025.

52013251207 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-52013251207 is a prime.

It is a super-2 number, since 2×520132512072 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (52013251237) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26006625603 + 26006625604.

It is an arithmetic number, because the mean of its divisors is an integer number (26006625604).

Almost surely, 252013251207 is an apocalyptic number.

52013251207 is a deficient number, since it is larger than the sum of its proper divisors (1).

52013251207 is an equidigital number, since it uses as much as digits as its factorization.

52013251207 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4200, while the sum is 28.

The spelling of 52013251207 in words is "fifty-two billion, thirteen million, two hundred fifty-one thousand, two hundred seven".