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52013414353 = 173059612609
BaseRepresentation
bin110000011100001111…
…011011011111010001
311222020220102012212211
4300130033123133101
51323010413224403
635521123552121
73520640504305
oct603417333721
9158226365784
1052013414353
112007124205a
12a0b722b641
134b9bc32a74
142735cbbd05
15154650706d
hexc1c3db7d1

52013414353 has 4 divisors (see below), whose sum is σ = 55073026980. Its totient is φ = 48953801728.

The previous prime is 52013414333. The next prime is 52013414359. The reversal of 52013414353 is 35341431025.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 39971205184 + 12042209169 = 199928^2 + 109737^2 .

It is a cyclic number.

It is not a de Polignac number, because 52013414353 - 29 = 52013413841 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (52013414359) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1529806288 + ... + 1529806321.

It is an arithmetic number, because the mean of its divisors is an integer number (13768256745).

Almost surely, 252013414353 is an apocalyptic number.

It is an amenable number.

52013414353 is a deficient number, since it is larger than the sum of its proper divisors (3059612627).

52013414353 is a wasteful number, since it uses less digits than its factorization.

52013414353 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3059612626.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 52013414353 its reverse (35341431025), we get a palindrome (87354845378).

The spelling of 52013414353 in words is "fifty-two billion, thirteen million, four hundred fourteen thousand, three hundred fifty-three".

Divisors: 1 17 3059612609 52013414353