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52014401 is a prime number
BaseRepresentation
bin1100011001101…
…0110101000001
310121212121100022
43012122311001
5101303430101
65054503225
71201054325
oct306326501
9117777308
1052014401
11273a720a
1215504b15
13aa1226a
146c9d985
154876a1b
hex319ad41

52014401 has 2 divisors, whose sum is σ = 52014402. Its totient is φ = 52014400.

The previous prime is 52014377. The next prime is 52014409. The reversal of 52014401 is 10441025.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 51854401 + 160000 = 7201^2 + 400^2 .

It is a cyclic number.

It is not a de Polignac number, because 52014401 - 26 = 52014337 is a prime.

It is a super-2 number, since 2×520144012 = 5410995822777602, which contains 22 as substring.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 52014401.

It is not a weakly prime, because it can be changed into another prime (52014409) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26007200 + 26007201.

It is an arithmetic number, because the mean of its divisors is an integer number (26007201).

Almost surely, 252014401 is an apocalyptic number.

It is an amenable number.

52014401 is a deficient number, since it is larger than the sum of its proper divisors (1).

52014401 is an equidigital number, since it uses as much as digits as its factorization.

52014401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 160, while the sum is 17.

The square root of 52014401 is about 7212.1010114945. The cubic root of 52014401 is about 373.2855688432.

Adding to 52014401 its reverse (10441025), we get a palindrome (62455426).

The spelling of 52014401 in words is "fifty-two million, fourteen thousand, four hundred one".