Base | Representation |
---|---|
bin | 110000011100011110… |
… | …110011000101000111 |
3 | 11222021011222220100021 |
4 | 300130132303011013 |
5 | 1323012431140033 |
6 | 35521350200011 |
7 | 3521016654121 |
oct | 603436630507 |
9 | 158234886307 |
10 | 52017443143 |
11 | 20073543a36 |
12 | a0b8653007 |
13 | 4b9ca13773 |
14 | 273664a211 |
15 | 1546a50b2d |
hex | c1c7b3147 |
52017443143 has 2 divisors, whose sum is σ = 52017443144. Its totient is φ = 52017443142.
The previous prime is 52017443131. The next prime is 52017443167. The reversal of 52017443143 is 34134471025.
52017443143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-52017443143 is a prime.
It is a super-2 number, since 2×520174431432 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 52017443099 and 52017443108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (52017443843) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26008721571 + 26008721572.
It is an arithmetic number, because the mean of its divisors is an integer number (26008721572).
Almost surely, 252017443143 is an apocalyptic number.
52017443143 is a deficient number, since it is larger than the sum of its proper divisors (1).
52017443143 is an equidigital number, since it uses as much as digits as its factorization.
52017443143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40320, while the sum is 34.
The spelling of 52017443143 in words is "fifty-two billion, seventeen million, four hundred forty-three thousand, one hundred forty-three".
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