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52018131 = 31110115607
BaseRepresentation
bin1100011001101…
…1101111010011
310121212210110110
43012123233103
5101304040011
65054532403
71201101234
oct306335723
9117783413
1052018131
11273a9aa0
1215507103
13aa13b79
146ca108b
154877ba6
hex319bbd3

52018131 has 16 divisors (see below), whose sum is σ = 76416768. Its totient is φ = 31212000.

The previous prime is 52018123. The next prime is 52018139. The reversal of 52018131 is 13181025.

It is an interprime number because it is at equal distance from previous prime (52018123) and next prime (52018139).

It is not a de Polignac number, because 52018131 - 23 = 52018123 is a prime.

It is a super-2 number, since 2×520181312 = 5411771905466322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 52018098 and 52018107.

It is not an unprimeable number, because it can be changed into a prime (52018139) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4471 + ... + 11136.

It is an arithmetic number, because the mean of its divisors is an integer number (4776048).

Almost surely, 252018131 is an apocalyptic number.

52018131 is a deficient number, since it is larger than the sum of its proper divisors (24398637).

52018131 is a wasteful number, since it uses less digits than its factorization.

52018131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15722.

The product of its (nonzero) digits is 240, while the sum is 21.

The square root of 52018131 is about 7212.3596000200. The cubic root of 52018131 is about 373.2944915124.

Adding to 52018131 its reverse (13181025), we get a palindrome (65199156).

The spelling of 52018131 in words is "fifty-two million, eighteen thousand, one hundred thirty-one".

Divisors: 1 3 11 33 101 303 1111 3333 15607 46821 171677 515031 1576307 4728921 17339377 52018131