Base | Representation |
---|---|
bin | 110000011100110101… |
… | …001011111100000011 |
3 | 11222021121001002002012 |
4 | 300130311023330003 |
5 | 1323020431442011 |
6 | 35522120043135 |
7 | 3521120566640 |
oct | 603465137403 |
9 | 158247032065 |
10 | 52023312131 |
11 | 2007689243a |
12 | a0ba6034ab |
13 | 4ba0cb9c3b |
14 | 2737336dc7 |
15 | 154730ea8b |
hex | c1cd4bf03 |
52023312131 has 16 divisors (see below), whose sum is σ = 62214243264. Its totient is φ = 42567617664.
The previous prime is 52023312079. The next prime is 52023312139. The reversal of 52023312131 is 13121332025.
52023312131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-52023312131 is a prime.
It is a super-2 number, since 2×520233121312 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 52023312097 and 52023312106.
It is not an unprimeable number, because it can be changed into a prime (52023312139) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1881200 + ... + 1908653.
It is an arithmetic number, because the mean of its divisors is an integer number (3888390204).
Almost surely, 252023312131 is an apocalyptic number.
52023312131 is a deficient number, since it is larger than the sum of its proper divisors (10190931133).
52023312131 is a wasteful number, since it uses less digits than its factorization.
52023312131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3789950.
The product of its (nonzero) digits is 1080, while the sum is 23.
Adding to 52023312131 its reverse (13121332025), we get a palindrome (65144644156).
The spelling of 52023312131 in words is "fifty-two billion, twenty-three million, three hundred twelve thousand, one hundred thirty-one".
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