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52040113 is a prime number
BaseRepresentation
bin1100011010000…
…1000110110001
310121220220121121
43012201012301
5101310240423
65055222241
71201222306
oct306410661
9117826547
1052040113
1127414564
1215517981
13aa20b88
146ca90ad
15487e45d
hex31a11b1

52040113 has 2 divisors, whose sum is σ = 52040114. Its totient is φ = 52040112.

The previous prime is 52040083. The next prime is 52040119. The reversal of 52040113 is 31104025.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 36096064 + 15944049 = 6008^2 + 3993^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-52040113 is a prime.

It is a super-2 number, since 2×520401132 = 5416346722105538, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (52040119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26020056 + 26020057.

It is an arithmetic number, because the mean of its divisors is an integer number (26020057).

Almost surely, 252040113 is an apocalyptic number.

It is an amenable number.

52040113 is a deficient number, since it is larger than the sum of its proper divisors (1).

52040113 is an equidigital number, since it uses as much as digits as its factorization.

52040113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120, while the sum is 16.

The square root of 52040113 is about 7213.8833508728. The cubic root of 52040113 is about 373.3470667957.

Adding to 52040113 its reverse (31104025), we get a palindrome (83144138).

The spelling of 52040113 in words is "fifty-two million, forty thousand, one hundred thirteen".