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52044344341133 is a prime number
BaseRepresentation
bin10111101010101100001001…
…01010000011001010001101
320211021101112211201001021212
423311112010222003022031
523310143304122404013
6302404501451304205
713651036240541444
oct1365260452031215
9224241484631255
1052044344341133
1115645978650791
125a0666174b065
1323069b70b2851
14cbcd61611d5b
15603bd5c166a8
hex2f5584a8328d

52044344341133 has 2 divisors, whose sum is σ = 52044344341134. Its totient is φ = 52044344341132.

The previous prime is 52044344341091. The next prime is 52044344341153. The reversal of 52044344341133 is 33114344344025.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 52024743501124 + 19600840009 = 7212818^2 + 140003^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-52044344341133 is a prime.

It is a super-2 number, since 2×520443443411332 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (52044344341153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26022172170566 + 26022172170567.

It is an arithmetic number, because the mean of its divisors is an integer number (26022172170567).

Almost surely, 252044344341133 is an apocalyptic number.

It is an amenable number.

52044344341133 is a deficient number, since it is larger than the sum of its proper divisors (1).

52044344341133 is an equidigital number, since it uses as much as digits as its factorization.

52044344341133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 829440, while the sum is 41.

Adding to 52044344341133 its reverse (33114344344025), we get a palindrome (85158688685158).

The spelling of 52044344341133 in words is "fifty-two trillion, forty-four billion, three hundred forty-four million, three hundred forty-one thousand, one hundred thirty-three".