Base | Representation |
---|---|
bin | 10111101010111110101100… |
… | …01111011011101101111101 |
3 | 20211022100020212201212101111 |
4 | 23311133112033123231331 |
5 | 23310324203033431031 |
6 | 302413230000442021 |
7 | 13651541104155256 |
oct | 1365372617335575 |
9 | 224270225655344 |
10 | 52054303030141 |
11 | 1564a11900a185 |
12 | 5a08580919311 |
13 | 2307913367839 |
14 | cbd62809db2d |
15 | 6040ba1641b1 |
hex | 2f57d63dbb7d |
52054303030141 has 2 divisors, whose sum is σ = 52054303030142. Its totient is φ = 52054303030140.
The previous prime is 52054303030133. The next prime is 52054303030199. The reversal of 52054303030141 is 14103030345025.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 40023602669241 + 12030700360900 = 6326421^2 + 3468530^2 .
It is a cyclic number.
It is not a de Polignac number, because 52054303030141 - 23 = 52054303030133 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (52054303034141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26027151515070 + 26027151515071.
It is an arithmetic number, because the mean of its divisors is an integer number (26027151515071).
Almost surely, 252054303030141 is an apocalyptic number.
It is an amenable number.
52054303030141 is a deficient number, since it is larger than the sum of its proper divisors (1).
52054303030141 is an equidigital number, since it uses as much as digits as its factorization.
52054303030141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 52054303030141 its reverse (14103030345025), we get a palindrome (66157333375166).
The spelling of 52054303030141 in words is "fifty-two trillion, fifty-four billion, three hundred three million, thirty thousand, one hundred forty-one".
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