Base | Representation |
---|---|
bin | 111011001011100000001100… |
… | …0001000010111010101110111 |
3 | 2112021010010200021010022101202 |
4 | 1312113000120020113111313 |
5 | 1021212144300411334033 |
6 | 5043041323223243115 |
7 | 214434346125351326 |
oct | 16627003010272567 |
9 | 2467103607108352 |
10 | 520550441121143 |
11 | 140955225322184 |
12 | 4a4721b55a949b |
13 | 1945c908073724 |
14 | 9278ac0a580bd |
15 | 402aaa18448e8 |
hex | 1d97018217577 |
520550441121143 has 2 divisors, whose sum is σ = 520550441121144. Its totient is φ = 520550441121142.
The previous prime is 520550441121089. The next prime is 520550441121419. The reversal of 520550441121143 is 341121144055025.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 520550441121143 - 220 = 520550440072567 is a prime.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 520550441121097 and 520550441121106.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (520550441921143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 260275220560571 + 260275220560572.
It is an arithmetic number, because the mean of its divisors is an integer number (260275220560572).
Almost surely, 2520550441121143 is an apocalyptic number.
520550441121143 is a deficient number, since it is larger than the sum of its proper divisors (1).
520550441121143 is an equidigital number, since it uses as much as digits as its factorization.
520550441121143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96000, while the sum is 38.
Adding to 520550441121143 its reverse (341121144055025), we get a palindrome (861671585176168).
The spelling of 520550441121143 in words is "five hundred twenty trillion, five hundred fifty billion, four hundred forty-one million, one hundred twenty-one thousand, one hundred forty-three".
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