Base | Representation |
---|---|
bin | 100101111000001111100… |
… | …0011011000111011010111 |
3 | 200102200122120121211101202 |
4 | 1023300133003120323113 |
5 | 1140243412431014413 |
6 | 15023340240543115 |
7 | 1045060030204604 |
oct | 113603703307327 |
9 | 20380576554352 |
10 | 5206021344983 |
11 | 1727952368328 |
12 | 700b66021a9b |
13 | 2b9c05a13864 |
14 | 13dd894316ab |
15 | 906495e7e58 |
hex | 4bc1f0d8ed7 |
5206021344983 has 2 divisors, whose sum is σ = 5206021344984. Its totient is φ = 5206021344982.
The previous prime is 5206021344971. The next prime is 5206021345009. The reversal of 5206021344983 is 3894431206025.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5206021344983 - 222 = 5206017150679 is a prime.
It is a super-3 number, since 3×52060213449833 (a number of 39 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5206021344913) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2603010672491 + 2603010672492.
It is an arithmetic number, because the mean of its divisors is an integer number (2603010672492).
Almost surely, 25206021344983 is an apocalyptic number.
5206021344983 is a deficient number, since it is larger than the sum of its proper divisors (1).
5206021344983 is an equidigital number, since it uses as much as digits as its factorization.
5206021344983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1244160, while the sum is 47.
The spelling of 5206021344983 in words is "five trillion, two hundred six billion, twenty-one million, three hundred forty-four thousand, nine hundred eighty-three".
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