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52064433 = 3223251519
BaseRepresentation
bin1100011010011…
…1000010110001
310121222010222100
43012213002301
5101312030213
65055531013
71201353231
oct306470261
9117863870
1052064433
1127430863
1215529a69
13aa2bc75
146cb3cc1
154886773
hex31a70b1

52064433 has 12 divisors (see below), whose sum is σ = 78474240. Its totient is φ = 33200376.

The previous prime is 52064431. The next prime is 52064447. The reversal of 52064433 is 33446025.

It is not a de Polignac number, because 52064433 - 21 = 52064431 is a prime.

It is a super-2 number, since 2×520644332 = 5421410367222978, which contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 52064397 and 52064406.

It is not an unprimeable number, because it can be changed into a prime (52064431) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 125553 + ... + 125966.

It is an arithmetic number, because the mean of its divisors is an integer number (6539520).

Almost surely, 252064433 is an apocalyptic number.

It is an amenable number.

52064433 is a deficient number, since it is larger than the sum of its proper divisors (26409807).

52064433 is a wasteful number, since it uses less digits than its factorization.

52064433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 251548 (or 251545 counting only the distinct ones).

The product of its (nonzero) digits is 8640, while the sum is 27.

The square root of 52064433 is about 7215.5687925485. The cubic root of 52064433 is about 373.4052167245.

The spelling of 52064433 in words is "fifty-two million, sixty-four thousand, four hundred thirty-three".

Divisors: 1 3 9 23 69 207 251519 754557 2263671 5784937 17354811 52064433