Base | Representation |
---|---|
bin | 10111101011100010111000… |
… | …10110010010101001010011 |
3 | 20211101012101222100200110021 |
4 | 23311301130112102221103 |
5 | 23311134001102002430 |
6 | 302430202001044311 |
7 | 13653126433645243 |
oct | 1365613426225123 |
9 | 224335358320407 |
10 | 52073732844115 |
11 | 156573896a3a84 |
12 | 5a102a3926697 |
13 | 23096bb884c98 |
14 | cc054c75db23 |
15 | 604855d0107a |
hex | 2f5c5c592a53 |
52073732844115 has 8 divisors (see below), whose sum is σ = 62561736721008. Its totient is φ = 41610148069920.
The previous prime is 52073732844047. The next prime is 52073732844277. The reversal of 52073732844115 is 51144823737025.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 52073732844115 - 221 = 52073730746963 is a prime.
It is a super-2 number, since 2×520737328441152 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6104770981 + ... + 6104779510.
It is an arithmetic number, because the mean of its divisors is an integer number (7820217090126).
Almost surely, 252073732844115 is an apocalyptic number.
52073732844115 is a deficient number, since it is larger than the sum of its proper divisors (10488003876893).
52073732844115 is a wasteful number, since it uses less digits than its factorization.
52073732844115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12209551349.
The product of its (nonzero) digits is 5644800, while the sum is 52.
The spelling of 52073732844115 in words is "fifty-two trillion, seventy-three billion, seven hundred thirty-two million, eight hundred forty-four thousand, one hundred fifteen".
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