Base | Representation |
---|---|
bin | 10111101011110100011001… |
… | …00100001100000111101011 |
3 | 20211102002200000000110210021 |
4 | 23311322030210030013223 |
5 | 23311312223210301423 |
6 | 302434354351501311 |
7 | 13653611362103161 |
oct | 1365721444140753 |
9 | 224362600013707 |
10 | 52083131728363 |
11 | 1566037206890a |
12 | 5a12087527837 |
13 | 230a558b75a58 |
14 | cc0ba0b29231 |
15 | 604c0602095d |
hex | 2f5e8c90c1eb |
52083131728363 has 2 divisors, whose sum is σ = 52083131728364. Its totient is φ = 52083131728362.
The previous prime is 52083131728357. The next prime is 52083131728387. The reversal of 52083131728363 is 36382713138025.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 52083131728363 - 229 = 52082594857451 is a prime.
It is a super-2 number, since 2×520831317283632 (a number of 28 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 52083131728363.
It is not a weakly prime, because it can be changed into another prime (52083131768363) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26041565864181 + 26041565864182.
It is an arithmetic number, because the mean of its divisors is an integer number (26041565864182).
Almost surely, 252083131728363 is an apocalyptic number.
52083131728363 is a deficient number, since it is larger than the sum of its proper divisors (1).
52083131728363 is an equidigital number, since it uses as much as digits as its factorization.
52083131728363 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4354560, while the sum is 52.
The spelling of 52083131728363 in words is "fifty-two trillion, eighty-three billion, one hundred thirty-one million, seven hundred twenty-eight thousand, three hundred sixty-three".
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