Base | Representation |
---|---|
bin | 10111101011110100011001… |
… | …00100001100001000000011 |
3 | 20211102002200000000110211011 |
4 | 23311322030210030020003 |
5 | 23311312223210302022 |
6 | 302434354351501351 |
7 | 13653611362103224 |
oct | 1365721444141003 |
9 | 224362600013734 |
10 | 52083131728387 |
11 | 15660372068931 |
12 | 5a12087527857 |
13 | 230a558b75a76 |
14 | cc0ba0b2924b |
15 | 604c06020977 |
hex | 2f5e8c90c203 |
52083131728387 has 2 divisors, whose sum is σ = 52083131728388. Its totient is φ = 52083131728386.
The previous prime is 52083131728363. The next prime is 52083131728483. The reversal of 52083131728387 is 78382713138025.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 52083131728387 - 27 = 52083131728259 is a prime.
It is a super-2 number, since 2×520831317283872 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (52083131728357) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26041565864193 + 26041565864194.
It is an arithmetic number, because the mean of its divisors is an integer number (26041565864194).
Almost surely, 252083131728387 is an apocalyptic number.
52083131728387 is a deficient number, since it is larger than the sum of its proper divisors (1).
52083131728387 is an equidigital number, since it uses as much as digits as its factorization.
52083131728387 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13547520, while the sum is 58.
The spelling of 52083131728387 in words is "fifty-two trillion, eighty-three billion, one hundred thirty-one million, seven hundred twenty-eight thousand, three hundred eighty-seven".
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